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Pronunciation varies by accent · adjective
(mathematics) That has a zero Jacquet functor for every proper parabolic subgroup.
A theorem of Bernstein states that for any compact open subgroup K of G(k), there are, up to unramified twists, only finitely many K-spherical supercuspidal representations of G(k).
Use supercuspidal when its meaning, tone and grammar fit the full sentence. A synonym is not always a direct replacement.
Supercuspidal means (mathematics) That has a zero Jacquet functor for every proper parabolic subgroup.
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The opposite depends on the specific sense.
A theorem of Bernstein states that for any compact open subgroup K of G(k), there are, up to unramified twists, only finitely many K-spherical supercuspidal representations of G(k).
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